Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Mixed Review of Problem Solving - Lessons 6.1-6.3 - Page 436: 5

Answer

See below

Work Step by Step

Evaluate $f(g(x))$: $$f_1(f_1(x))=f_1(x)=x$$ Evaluate $f(y)$: $$f_2(f_2(x))=f_2(-x)=-(-x)=x$$ Hence, the solution is $f_1(x)=x$. Another solution is $f_2(x)=-x$
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