Answer
See the graph
Work Step by Step
We are given: $y=(x-3)^2-4$
Hence here, $a=1,h=3,k=-4$
The vertex is $(3,-4)$
The axis of symmetry is: $x=3$
Make a list of values:
$x=0 \rightarrow y=5$
$x=6 \rightarrow y=5$
$x=1 \rightarrow y=0$
$x=5 \rightarrow y=0$