Answer
See the graph
Work Step by Step
We are given: $y=x^2-x-2$
$y=(x^2-x+\frac{1}{4})-\frac{1}{4}-2$
$y=(x-\frac{1}{2})^2-\frac{9}{4}$
Hence here, $a=1,h=\frac{1}{2},k=-\frac{9}{4}$
The vertex is $(\frac{1}{2},\frac{-9}{4})$
The axis of symmetry is: $x=\frac{1}{2}$
Make a list of values:
$x=0 \rightarrow y=-2$
$x=1 \rightarrow y=-2$
$x=2 \rightarrow y=0$
$x=-1 \rightarrow y=0$