Answer
$\frac{1}{27x^6y^3}$
Work Step by Step
Apply the Quotient of Powers Property:
$(3x^{2}y)^{-3}=3x^{-3}(x^2)^{-3}y^{-3}$
Apply the Negative Exponent Property: $3x^{-3}(x^2)^{-3}y^{-3}=\frac{1}{27x^6y^3}$
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