Answer
See below
Work Step by Step
Given: $f(x)=x^3-8x^2+4x-32$
Let $f(x)=0$, $x^3-8x^2+4x-32=0$
Simplify: $x^2(x-8)+4(x-8)=0\\ \Leftrightarrow (x-8)(x^2+4)=0\\ \Leftrightarrow x=8 \lor x=\pm 2i$
Hence, the zeros are $8$ or $2i,-2i$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - 6.1 Evaluate nth Roots and Use Rational Exponents - 6.1 Exercises - Mixed Review - Page 419: 71
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