Chapter 5 Polynomials and Polynomial Functions - Standardized Test Practice - Short Response - Page 410: 7

$B=2x^2+11x+14$

Let $B$ be the area of its base. $h$ is its height. The volume of a prism is $V=B.h$ Substitute: $2x^3+5x^2-19x-42=B(x-3)\\ \rightarrow B=(2x^3+5x^2-19x-42)\div(x-3)$ Applying synthetic division: $2x^2+\frac{11x^2-19x-42}{x-3}\\ 2x^2+11x+\frac{14x-42}{x-3}\\ 2x^2+11x+14$ Hence, $B=2x^2+11x+14$