Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - Standardized Test Practice - Short Response - Page 410: 1

Answer

See below

Work Step by Step

The year 1980 is $20$ years after the year 1960; substitute $x=20$: $y=-0.0006(20)^3+0.0383(20)^2+0.383(20)+68.6\\=-0.0006(8000)+0.0383(400)+0.383(20)+68.6\\=-4.8+15.32+7.66+68.6\\=86.78$ In the year 1980, $86.78$ million people voted. The year 1960 is $0$ years after the year 1960; substitute $x=0$: $y=-0.0006(0)^3+0.0383(0)^2+0.383(0)+68.6\\=-0.0006(0)+0.0383(0)+0.383(0)+68.6\\=0+68.6\\=68.6$ In the year 1960, $68.6$ million people voted. The difference between the number of voters: $86.78-68.8=18.18$ people
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