Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - Prerequisite Skills - Page 328: 12

Answer

$$x=3\pm3\sqrt3$$

Work Step by Step

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{-6\pm \sqrt{(6)^2-4(1)(-18)}}{2(1)}$$ $$x=3\pm3\sqrt3$$
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