Answer
$$x=\frac{-1\pm\sqrt{47}i}{4}$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{-1\pm \sqrt{(1)^2-4(2)(6)}}{2(2)}$$
$$x=\frac{-1\pm\sqrt{47}i}{4}$$
