Answer
$f(x)=2(x+2)(x+1)(x-2)$
Work Step by Step
Here, we have $f(x)=a (x-(-2))(x-(-1))(x-2)$
or, $f(x)=a (x+2)(x+1)(x-2)$
When $x=0$, then we have $-8=a (0+2)(0+1)(0-2)$
or, $-4a=-8$
This gives: $a=2$
Thus, we have $f(x)=2(x+2)(x+1)(x-2)$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.9 Write Polynomial Functions and Models - 5.9 Exercises - Skill Practice - Page 397: 7
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