Answer
$f(x)=\dfrac{1}{6}(x+3)(x-1)(x-4)$
Work Step by Step
Here, we have $f(x)=a (x+3)(x-1)(x-4)$
When $x=0$, then we have $2=a (0+3)(0-1)(0-4)$
or, $12a=2$
This gives: $a=\dfrac{1}{6}$
Thus, we have $f(x)=\dfrac{1}{6}(x+3)(x-1)(x-4)$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.9 Write Polynomial Functions and Models - 5.9 Exercises - Skill Practice - Page 397: 5
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
