Answer
Positive real zeros = 1
Negative real zeros= 2
Imaginary zeros = 0
Work Step by Step
In the given polynomial of degree $3$, there are $3$ zeros.
By Descartes' Rule, we can notice form the graph that the function has $2$ Negative real zeros (approximately -1 and -2.8) and $1$ Positive real zero (approximately 1.8).
Hence, Positive real zeros = 1
Negative real zeros= 2
Imaginary zeros = 0