Answer
See below
Work Step by Step
Build a table of values for $y^4+y^3$
To solve $ax^4+bx^3=c$, we multiply both sides by $\frac{a^3}{b^4}$
As a result, $(\frac{ax}{b})^4+(\frac{ax}{b})^3=\frac{a^3c}{b^4}$
Thus, we will find $y$ that gives a value close to $\frac{a^3c}{b^4}$ in the table and solve $\frac{ax}{b}=y$.
