Answer
See the graph
Work Step by Step
Givne: $4x+12y\leq4 \rightarrow y \leq\frac{1}{3}-\frac{1}{3}x$
Draw the line $y =\frac{1}{3}-\frac{1}{3}x$ using two points such as $(0,\frac{1}{3})$ and $(1,0)$. The solution region is below and including the boundary line.