Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Chapter Review - Page 319: 18

Answer

-15, 3

Work Step by Step

We first try to get zero on one side of the equation. After getting zero on one side of the equation, we factor the equation in order to solve. Doing this, we find: $$k^2 -12k +45 =0 \\ (k+15)(k-3) =0 \\ k =3, -15$$
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