Answer
See below
Work Step by Step
Given: $-6x^2+19x \geq 10$
Rewrite as: $-6x^2+19x -10\geq 0$
The graph is equal to $0$ at $x=0.667$ and $x=2.5$
Thus, the answer is $0.667 \leq x \leq 2.5$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.9 Graph and Solve Quadratic Inequalities - 4.9 Exercises - Skill Practice - Page 305: 41
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