Answer
See below
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Work Step by Step
Given: $-6x^2+19x \geq 10$
Rewrite as: $-6x^2+19x -10\geq 0$
The graph is equal to $0$ at $x=0.667$ and $x=2.5$
Thus, the answer is $0.667 \leq x \leq 2.5$
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