Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - Guided Practice for Example 5 - Page 255: 12

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Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $25$ and add to get $-10$. Thus, we find that the solution is: $$(x-5)(x-5)$$ Thus, setting each factor equal to zero, we find that the zeros are: $$5$$