Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - Guided Practice for Example 5 - Page 255: 10

-7,2

Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-14$ and add to get $5$. Thus, we find that the solution is: $$(x+7)(x-2)$$ Thus, setting each factor equal to zero, the zeros are: $$-7,2$$