Answer
$x=8$.
Work Step by Step
Our equation is according to the text of the exercise: $3\cdot12\cdot10=(12+x)(10+x)\\360=120+x^2+22x\\x^2+22x-240=0\\(x-8)(x+30)=0$
Thus $x=8$ or $x=-30$ but $x$ has to be positive, thus $x=8$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 256: 43
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