Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 256: 18

$$(t-8)^2$$

Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (t\pm a)(t\pm b)$$ Here, we see that a and b must multiply to get $64$ and add to get $-16$. Thus, we find that the solution is: $$(t-8)(t-8)=(t-8)^2$$