Answer
$(q-7)(q-4)$
Work Step by Step
We try to find factors of c in $x^2+bx+c$ that add to negative b,
In this case...
$q^2-11q+28$
$q^2-7q-4q+28$
$q(q-7)-4(q-7)$
$(q-7)(q-4)$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 255: 8
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