Answer
See the graph
Work Step by Step
Given: $y=(x+4)(x-2)$
$y=x^2+2x-8$
The coefficients are $a=1, b=2$, and $c=-8$. Because $a \gt 0$, the parabola opens up.
Find the vertex:
$x=\frac{-b}{2a}=\frac{-2}{2.1}=-1$
then $y=(-1+4)(-1-2)=-9$
The vertex is $(-1,-9)$.
Draw the axis of symmetry $x=-1$.
The y-intercept is $-8$. Plot the point $(0,-8)$. Then reflect this point in the axis of symmetry to plot another point, $(-2,-8)$.
Evaluate the function for another value of x, such as $x=−4$.
$y=(-4+4)(-4-2)=0$
Plot the point $(-4,0)$ and its reflection $(2,0)$ in the axis of symmetry.
Draw a parabola through the plotted points.
