Answer
See the graph
Work Step by Step
Given: $y=-2(x+1)^2-4$
$y=-2x^2-4x-6$
The coefficients are $a=-2, h=-1$, and $k=-4$. Because $a\lt0$, the parabola opens down.
The vertex is $(-1,-4)$.
Draw the axis of symmetry $x=-1$.
The y-intercept is $-6$. Plot the point $(0,-6)$. Then reflect this point in the axis of symmetry to plot another point, $(-2,-6)$.
Evaluate the function for another value of x, such as $x=−3$.
$y=-2(-3+1)^2-4=-12$
Plot the point $(-3,-12)$ and its reflection $(1,-12)$ in the axis of symmetry.
Draw a parabola through the plotted points.
