Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Cumulative Review Chapters 1-3 - Page 232: 36

Answer

$(C-A)B=\begin{bmatrix} 4&6\\ 16 & 24 \end{bmatrix}$

Work Step by Step

$(C-A)B=(\begin{bmatrix} -4 & 8\\ -7 & 12 \end{bmatrix}-\begin{bmatrix} -2 & 6\\ 1 & 4 \end{bmatrix})\begin{bmatrix} 3 & -1\\ 5 &2 \end{bmatrix}$ $=\begin{bmatrix} -2& 2\\ -8 & 8 \end{bmatrix}\begin{bmatrix} 3 & -1\\ 5 &2 \end{bmatrix}$ $=\begin{bmatrix} 4&6\\ 16 & 24 \end{bmatrix}$
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