Answer
Each bouquet should include 8 roses, 2 lilies and 2 irises.
Work Step by Step
We have:
$r+l+i=12$
$2.5r+4l+2i=32$
$r=2(l+i) \rightarrow r-2l-2i=0$
Use elimination for the first and third equations:
$r+l+i=12$
$r-2l-2i=0$
Multiply both sides of the first equation by 2:
$2r+2l+2i=24$
$r-2l-2i=0$
_____________________
$3r=24$
$r=8$
Substitute for r in the first equation:
$8+l+i=12$
$l=4-i$
Substitute for r in the second equation:
$2.5(8)+4(4-i)+2i=32$
$20+16-4i+2i=32$
$-2i=-4$
$i=2$
Solve for l: $l=4-i=4-2=2$
