Answer
$r+l+i=12$
$2.5r+4l+2i=32$
$r=2(l+i)$
Work Step by Step
Let r = the number of roses
l = the number of lilies
i= the number of irises
She has a budget of $\$160$ and wants 12 flowers for each bouquet. Roses cost $\$2.50$ each, lilies cost $\$4$ each, and irises cost $\$2$ each.
$r+l+i=12$
$5(2.5r+4l+2i)=160$
She wants twice as many roses as the other two types of flowers combined:
$r=2(l+i)$
Hence, we have the system of equations:
$r+l+i=12$
$5(2.5r+4l+2i)=160$
$r=2(l+i)$
Simplify:
$r+l+i=12$
$2.5r+4l+2i=32$
$r=2(l+i)$
