Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.2 Solve Linear Systems Algebraically - 3.2 Exercises - Problem Solving - Page 166: 59

Answer

$12$ doubles and $14$ singles matches.

Work Step by Step

Let $x$ be the number of doubles games. Then the number of singles games is $26-x$. Then our equation is: $4x+(26-x)2=76\\4x+52-2x=76\\2x=24\\x=12$ Thus there were $12$ doubles and $14$ singles matches.
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