Answer
$d^2\gt\frac{25}{9}h^2$
Work Step by Step
We know that $w\gt \frac{4}{3}h$ and that by the Pythagorean Theorem, $d^2=w^2+h^2$.
Hence $d^2=w^2+h^2\gt(\frac{4}{3}h)^2+h^2=\frac{16}{9}h^2+h^2=\frac{25}{9}h^2$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 2 Linear Equations and Functions - 2.8 Graph Linear Inequalities in Two Variables - 2.8 Exercises - Problem Solving - Page 138: 49b
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