Answer
Yes.
Work Step by Step
Plugging in $w=27.4,h=16.5$ we get: $\frac{w}{h}=\frac{27.4}{16.5}\approx1.66\gt\frac{4}{3}$. Thus it meets the requirements.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 2 Linear Equations and Functions - 2.8 Graph Linear Inequalities in Two Variables - 2.8 Exercises - Problem Solving - Page 138: 49a
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