Answer
See below.
Work Step by Step
Using the given formula and the known values: $\sin\frac{23\pi}{12}=\sin3\pi/4\cos7\pi/6+\sin7\pi/6\cos3\pi/4=\frac{1}{\sqrt2}(-\frac{\sqrt3}{2})+(-\frac{1}{2})(-\frac{1}{\sqrt2})=-\frac{\sqrt3-1}{2\sqrt2}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.6 Apply Sum and Difference Formulas - 14.6 Exercises - Skill Practice - Page 952: 7
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