Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13 Trigonometric Ratios and Functions - Chapter Review - Page 900: 21

Answer

See below.

Work Step by Step

$A=180-60-73=47^\circ$. Using the law of sines, $\frac{a}{\sin47^\circ}=\frac{20}{\sin60^\circ}\\a=\frac{20\sin47^\circ}{\sin60^\circ}\approx16.89$ $\frac{c}{\sin73^\circ}=\frac{20}{\sin60^\circ}\\c=\frac{20\sin73^\circ}{\sin60^\circ}\approx22.08$
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