Answer
$$\frac{x+2}{x-5}$$
Work Step by Step
Simplifying the expression by cancelling terms in the numerator and the denominator, we find:
$$\frac{\left(4x^2-16\right)\left(x+5\right)}{\left(x^2-25\right)\left(4x-8\right)} \\ \frac{\left(x+2\right)\left(x-2\right)\left(x+5\right)}{\left(x+5\right)\left(x-5\right)\left(x-2\right)} \\ \frac{x+2}{x-5}$$
