Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - 13.5 Exercises - Mixed Review - Page 888: 57

Answer

$$2x^3y^2z^2$$

Work Step by Step

Simplifying the expression by cancelling terms in the numerator and the denominator, we find: $$\frac{40x^3y^3}{2xyz}\times \frac{x^2yz^3}{10xy} \\ \frac{40x^3y^3x^2z^3}{2xz10xy} \\ 2x^3y^2z^2$$
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