Answer
See below
Work Step by Step
Let us consider $\sin \theta = 0.15$ ; $90^{\circ} \lt \theta \lt 180^{\circ}$
and $\theta =\sin^{-1} (-0.15) \approx 8^{\circ}$
So, the reference angle is: $\theta = 180^{\circ}-8^{\circ}=172^{\circ}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Skill Practice - Page 878: 22
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