Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Skill Practice - Page 878: 21

Answer

$206.74^{\circ}$

Work Step by Step

Let us consider $\sin \theta = -0.45$ ; $180^{\circ} \lt \theta \lt 270^{\circ}$ and $\theta =\sin^{-1} (-0.45) \approx -26.74^{\circ}$ So, the reference angle is: $\theta = 180^{\circ}+26.74^{\circ}=206.74^{\circ}$
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