Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Skill Practice - Page 857: 24

Answer

$c \approx 17.9 \\ a \approx 16.5 \\B =23^{\circ}$

Work Step by Step

Here, $\cos A=\dfrac{b}{c}$ This gives: $\cos 67^{\circ}=\dfrac{7}{c} \implies c \approx 17.9$ $\sin A=\dfrac{a}{c}$ This gives: $\sin 67^{\circ}=\dfrac{a}{17.9} \implies a \approx 16.5$ Since the sum of a triangle is $180^{\circ}$ and the right angle is $90^{\circ}$: $ B=A-C=180^{\circ}-157^{\circ}=23^{\circ}$
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