Answer
$c \approx 17.9 \\ a \approx 16.5 \\B =23^{\circ}$
Work Step by Step
Here, $\cos A=\dfrac{b}{c}$
This gives: $\cos 67^{\circ}=\dfrac{7}{c} \implies c \approx 17.9$
$\sin A=\dfrac{a}{c}$
This gives: $\sin 67^{\circ}=\dfrac{a}{17.9} \implies a \approx 16.5$
Since the sum of a triangle is $180^{\circ}$ and the right angle is $90^{\circ}$:
$ B=A-C=180^{\circ}-157^{\circ}=23^{\circ}$