Answer
$(y-2)^2=-8(2x+14)$; parabola
Work Step by Step
Given: $y^2-4y+16x+116=0$
$(y-2)^2+16x+112=0$
This gives:
$(y-2)^2=-8(2x+14)$
Thus, we have
$(y-2)^2=-8(2x+14)$
This is the standard form of a parabola.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Mixed Review - Page 858: 52
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