Answer
a) $1,2,4,8,16,32,64,128,256,512$
b) see graph
c) $1023$
Work Step by Step
a) In order to find the first ten terms of the given sequence $a_n=2^{n-1}$ put the graphing calculator in $\textit{sequence}$ mode and $\textit{dot}$ mode, enter the sequence ($2^{n-1}$), then use the $\textit{table}$ feature to see the terms of the sequence. The first ten terms are:
$$\begin{align*}
a_1&=1\\
a_2&=2\\
a_3&=4\\
a_4&=8\\
a_5&=16\\
a_6&=32\\
a_7&=64\\
a_8&=128\\
a_9&=256\\
a_{10}&=512.
\end{align*}$$
b) We set the viewing window so that $0\leq n\leq 10$, $0\leq x\leq 11$ and $0\leq y\leq 530$. Graph the sequence and use the $\textit{trace}$ feature to view the terms.
c) With the $\textit{summation}$ feature we find the sum of the first ten terms of the sequence:
$$sum(seq(2^{n-1},n,1,10))=1023.$$
