Answer
a) $9,12,15,18,21,24,27,30,33,36$
b) see graph
c) $225$
Work Step by Step
a) In order to find the first ten terms of the given sequence $a_n=3n+6$ put the graphing calculator in $\textit{sequence}$ mode and $\textit{dot}$ mode, enter the sequence ($3n+6$), then use the $\textit{table}$ feature to see the terms of the sequence. The first ten terms are:
$$\begin{align*}
a_1&=9\\
a_2&=12\\
a_3&=15\\
a_4&=18\\
a_5&=21\\
a_6&=24\\
a_7&=27\\
a_8&=30\\
a_9&=33\\
a_{10}&=36.
\end{align*}$$
b) We set the viewing window so that $0\leq n\leq 10$, $0\leq x\leq 11$ and $0\leq y\leq 40$. Graph the sequence and use the $\textit{trace}$ feature to view the terms.
c) With the $\textit{summation}$ feature we find the sum of the first ten terms of the sequence:
$$sum(seq(3n+6,n,1,10))=225.$$
