Answer
See below.
Work Step by Step
According to the exercise:
$a_0=3$
$a_1=(a_0)^2-5=3^2-5=4$
$a_2=(a_1)^2-5=4^2-5=11$
$a_3=(a_2)^2-5=11^2-5=116$
$a_4=(a_3)^2-5=116^2-5=13451$
$a_5=(a_4)^2-5=13451^2-5=180929396$
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