Answer
$\frac{13}{33}$
Work Step by Step
$0.3939...=39(0.01)+39(0.01)^2+...=\frac{a_1}{1-r}=\frac{39(0.01)}{1-0.01}=\frac{0.39}{0.99}=\frac{39}{99}=\frac{13}{33}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.5 Use Recursive Rules with Sequences and Functions - 12.5 Exercises - Quiz for Lessons 12.4-12.5 - Page 833: 5
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