Answer
See below
Work Step by Step
$$a_n+d=0.7a_{n-1}+40+d\\a_n+d=0.7(a_{n-1}+\frac{40+d}{0.7})\\\rightarrow d=\frac{40+d}{0.7}=\frac{-400}{3}$$
The maintenance level of this drug is $a_n-\frac{400}{3}=0.7(a_{n-1}-\frac{400}{3})\\a_n \rightarrow \frac{400}{3}$