Answer
$\dfrac{7}{10}$
Work Step by Step
Here, we have $a_n= a_1 r^{n-1}$ for the Geometric series.
First term $a_1=1$ and Common ratio $r=\dfrac{-3}{7}$
The sum of an infinite Geometric Series can be found using: $S_n=\dfrac{a_1}{1-r}$
Thus, $S_n=\dfrac{1}{1-(\dfrac{-3}{7})}=\dfrac{1 \times 7}{7+3}$
Hence, $S_n=\dfrac{7}{10}$