Answer
$\dfrac{-8}{5}$
Work Step by Step
Here, we have $a_n= a_1 r^{n-1}$ for the Geometric series.
First term $a_1=-2$ and Common ratio $r=\dfrac{-1}{4}$
The sum of an infinite Geometric Series can be found using: $S_n=\dfrac{a_1}{1-r}$
Thus, $S_n=\dfrac{-2}{1-(-1/4)}=\dfrac{-2 \times 4}{4+1}$
Hence, $S_n=\dfrac{-8}{5}$