Chapter 12 Sequences and Series - 12.4 Find Sums of Infinite Geometric Series - 12.4 Exercises - Mixed Review - Page 825: 47

$a_n=8n-35$

Here, we have $a_n= a_1+d(n-1)$ for the Arithmetic series. The common difference between the successive terms is $d=8$ First term is: $a_1=-27$ Here, we have $a_n= a_1+d(n-1)=-27+8 \times (n-1)$ Hence, $a_n=8n-35$