Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Problem Solving - Page 816: 61a

Company A: Arithmetic Company B: Geometric

Here, we have $a_1= 20,000$ and $b_1= 20,000$ We know that $a_n=a_1+(n-1)d$ Plug in $d=1000$ $a_n=20,000+(n-1) \times (1000)$ ...(1) And $r=1+0.04=1.04$ Thus, $b_n=b_1r^{n-1}=20,000(1.04)^{n-1}$ ...(2) From equations (1) and (2), we have Company A: Arithmetic Company B: Geometric