Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Problem Solving - Page 816: 59a

Answer

See below

Work Step by Step

We can see that after the 1st pass, $\frac{1024}{2}=512$ items will be searched. After the 2nd pass, $\frac{512}{2}=216$ items. For the 3rd pass, $\frac{216}{2}=108$ items. After the 4th pass, $\frac{108}{2}=54$ items will be left to be searched. The rule for the number of items remaining after the nth pass through an ordered list of 1024 items is $\frac{1024}{2^n}$
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