Answer
See below
Work Step by Step
We can see that after the 1st pass, $\frac{1024}{2}=512$ items will be searched.
After the 2nd pass, $\frac{512}{2}=216$ items.
For the 3rd pass, $\frac{216}{2}=108$ items.
After the 4th pass, $\frac{108}{2}=54$ items will be left to be searched.
The rule for the number of items remaining after the nth pass through an ordered list of 1024 items is $\frac{1024}{2^n}$