Answer
136
Work Step by Step
Applying the formula, we find:
$$\sum _{k=1}^nk=\frac{1}{2}n\left(n+1\right)\\ \frac{1}{2}\cdot \:16\left(16+1\right) \\ 136$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 799: 54
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