Answer
7
Work Step by Step
Solving the equation for x, we find:
$$\left(\sqrt{x-3}\right)^2=\left(x-5\right)^2 \\ x-3=x^2-10x+25 \\ x=7,\:x=4$$
Plugging this back in, we find that 7 satisfies the equation but $x=4$ does not.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - 11.3 Use Normal Distributions - 11.3 Exercises - Mixed Review - Page 762: 53
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