Answer
See below
Work Step by Step
We find $\frac{g(x)}{f(x)}=\frac{6x^2}{4x-9}$
The numerator can't be equal to $0$, thus $4x-9=0\\x=\frac{9}{4}$
The domain is all real numbers except $\frac{9}{4}$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - 11.3 Use Normal Distributions - 11.3 Exercises - Mixed Review - Page 762: 46
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
